Correct graph with comparison of power consumption has to be done in way that you can deduce total power consumption in Watt-hours during constant time e.g. 8 hours while doing same tasks.
Originally Posted by iniudan
You can compare total consumption if you know that machine is idle 3 hours and 5 hours is used for video watching.
Average power consumption graph at silent PC is assuming 50% of time on heavy load. If fast CPU encodes videos 4 hours it will encode more videos than slow CPU.
If same tasks are done slow CPU spend more % of time on heavy load than fast CPU which means constant split 50:50 is wrong.
$75 35W 2.6Ghz Pentium G2100T and G2020T are tray/OEM only which means limited availability and warranty.
You can get 35W CPU by underclocking and undervolting of 55W CPU, but it will mean 1W / 2W / 3W lower power in idle / low load / full load in average.
2W lower power means about $2 lower bill per year.
Hand Brake encoding in 1 hour on slower CPU
2100T - 100% load (64 W) = 64 Wh
2100 - 81.25% load (74 W) + 18.75% idle (38W) - 74*0.8125+38*(1-0.8125) = 67.25 Wh
55W 2.6 GHz Celeron G1610 - $50
55W 2.7 GHz Celeron G1620 - $60 - 0.88V
55W 2.9 GHz Pentium G2020 - $65 - 0.976V
Celeron has lower voltage than Pentium, which means lower power at full load.
Last edited by JS987; 04-07-2013 at 01:19 PM.